the vapor pressure of water at 45.0 °c is 71.93 mmhg. Calculate the vapor pressure of a solution of 1.50 m Al(NO3)3 at this temperature (assume 100% dissociation)

Answer 1

1.50 m means 1.5 mols AlCl3/kg solvent.
mols in 1 kg solvent = 1000/molar mass H2O = about 55.5 mols.
1.5 mols AlCl3 = 4*1.5 = 6 mols AlCl3 as ions.
Total mols = 6.0 + 55.5 = about 61.5
XH2O = nH2O/total mols

pH2O = XH2O*P^o_H2O

Answer 2

no

Answer 3

no

Answer 4

Please I need the full workings