The vapor pressure of pure ethanol at 20 degrees C is 44 mmHg, and the vapor pressure of pure methanol at the same temperature is 94 mmHg. In a solution of the two, the mole fraction of ethanol is .439; the mole fraction for methanol is .561. Calculate the vapor pressure of each component of the solution.

2 answers

Pethanol = Xethanol*Poethanol
The methanol is done the same way.
Pethanol means partial pressure of the ethanol above the solution.