Of course we see no "following exponential function".
let's assume it looks something like this
f(x) = 130000(e)^(.06x) , in this case the rate of increase would be 6%
f ' (x) = 130000(.06)(e^.06x)
so if x = 5 we get f ' (x) = $10,429
Change my solution to reflect your actual case
the base could be something like 1.06^x
The value of a family's home, in Camrose AB, is given by the following exponential function f(x), where x is the number of years after the family purchases the house for $130,000. What is the best estimate for the instantaneous rate of change in the value of the home when the family has owned it for 5 years?
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