it dropped 6K in 2 years. That's 3K per year.
So, it started at 3K more than 20K.
y = 23000 - 3000x
The value of a car decreases at a constant rate. After 1 year the value of the car is $20,000. After 2 more yearsit is $14,000. Write an equation in slope-intercept that represents the value y (in dollars) of the car after x years.
3 answers
steve how did you get that
get what? They told you that the value dropped from 20K to 14K in two years.
If you can't see how that relates to the slope of the graph, then you seriously need to review your text or look at examples online.
Since it dropped 3K in one year, and a year after it was bought it was worth 20K, then that means that in the beginning, it was worth 3K more -- $23K.
So, at time x=0 (0 years after purchase), y= 23000
If you can't see how that relates to the slope of the graph, then you seriously need to review your text or look at examples online.
Since it dropped 3K in one year, and a year after it was bought it was worth 20K, then that means that in the beginning, it was worth 3K more -- $23K.
So, at time x=0 (0 years after purchase), y= 23000
0 answers