dT/dx=2.5+x
dT=2.5dx+xdx x=25, dx=1 solve for dT
The total stopping distance T of a vehicle is T=2.5x+0.5x^2 where T is in feet and x is the speed in miles per hour. Approximate the change and percent change in total stopping distance as sped changes from x=25 to x=26 miles per hour.
I started taking the derivative, but that just left me with no where to go....
2 answers
dt= 2.5+x(dx)
2.5+25=27.5
dx=1 --- because change on x (26-25=1)
so dt=27.5(1)= 27.5ft
2.5+25=27.5
dx=1 --- because change on x (26-25=1)
so dt=27.5(1)= 27.5ft
1 answer