since this is calculus, and you want to approximate the change ∆T, you must want to use
∆T ≈ T' ∆x
So, plug in your numbers to get ∆T. Then of course, the % change is
∆T/T(15)
The total stopping distance T of a vehicle is shown below, where T is in feet and x is the speed in miles per hour.
T = 2.5x + 0.5x^2
Approximate the change and percent change in total stopping distance as speed changes from x = 15 to x = 18 miles per hour. (Round your answers to one decimal place.)
1 answer