the total pressure of n2o4 and no2 IS 1.38 atm. if kp is 6.75(25 C) calculate partial pressure of NO2 in the mixture. 2NO2<---> n2o4

Answer 1

I assume the system is at equilibrium?? If so, the way I see it is
total pressure = 1.38 atm..
partial pressure N2O4 = x
partial pressure NO2 = 2x
3x = 1.38 and solve for x, then
2x = partial pressure NO2.

Answer 2

I don't think that is the right interpretation for the problem.
2NO2 ==> N2O4
If total P is 1.38, then
pNO2 = x
pN2O4 = 1.38-x
Then Kp = 6.75 = pN2O4/p(NO2)^2
Substitute x and 1.38-x into the above Kp expression and solve for x.

Answer 3

Nothing

Answer 4

Good

Answer 5

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