The total area enclosed by the graphs of y=6(x^2)–(x^3)+x and y=(x^2)+7x is ..

Answer 1

graph those two functions to get your limits
The second x(x+7) is a parabola right side up (holds water) with zeros at x = 0 and x = -7
The first x ( -x^2 + 6x + 1) is a cubic with zero at zero.
These two curves intersect at x+7 = -x^2+6x+1
which is at x = 2 and x = 3
Does that help ?

Answer 2

Yeah. Thanks. I found out that the limits are from 0 to 2 and 2 to 3.