Asked by Willoby
A home gardener plans to enclose two rectangular gardens with fencing. The dimensions of the garden: x by 12-x, y by 12-x-y
a. Find the values of x and y that maximize the total area enclosed.
b. What is the maximum total area enclosed?
c. How many meters of fencing are needed?
a. Find the values of x and y that maximize the total area enclosed.
b. What is the maximum total area enclosed?
c. How many meters of fencing are needed?
Answers
Answered by
Mgraph
The total area A=A(x,y).
A=x(12-x)+y(12-x-y)=12x-x^2+12y-xy-y^2
Partial derivatives
A'x=12-2x-y
A'y=12-x-2y
Solve the equations A'x=A'y=0 => a. x=y=4
b. Amax=32+16=48
c. 24+16=40
A=x(12-x)+y(12-x-y)=12x-x^2+12y-xy-y^2
Partial derivatives
A'x=12-2x-y
A'y=12-x-2y
Solve the equations A'x=A'y=0 => a. x=y=4
b. Amax=32+16=48
c. 24+16=40
Answered by
Willoby
hey thanks! but where did you get 16 in b?
Answered by
Mgraph
y(12-x-y)=4(12-4-4)=16
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