T= k sqrt L
15 = k sqrt 9 = k * 3
k = 5
so
T = 5 sqrt L
80 = 5 sqrt L
16 = sqrt L
L = 16^2 = 256 cm
The time of a pendulum varies directly as the square root of it length if the length of the pendulum which beats 15 seconds is 9 centimetre find the length that beats 80 seconds
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how do we solve the question:- the time of pendulum varies the square root of it length if the length of a pendulum which beats 15seconds is 9cm.Find (a)the length that beat 80seconds (b)the time of a pendulum with length 36seconds
How do I solve the question
3 answers