The third term of a geometric progressiom is nine times the first term.if the second term is one-twenty fourth the fifth term.find the fourth term.ar^2=9a. r=sqr of 9 r=3.pls teach me how to get the first term and i can get the 4th term myself

Answer 1

a ar^1 ar^2 ar^3 .... ar^(n-1)

so
a r^2 = 9 a
a r^1 = (1/24)ar^4
-----------------------
-----------------------
so
r = 3

a(3) = (1/24)a (3)^4
This is not possible. You have a typo.