The third-tallest Ferris Wheel in the world is the London Eye in England. The height (in metres) of a rider on the London Eye after t minutes can be described by the function h(t) = 67sin [12(t + 0.0223)] + 70.

Question

At what time(s) will the rider be at the bottom of the Ferris wheel?
How long does it take for the Ferris wheel to go through one rotation?

Answer 1

h(t)= 67sin(12(t+0.0223))+70
h(0)=67sin(12(0-0.0223))+70
h(0)= 67sin(12(0.0223)+70
h(0)= 67sin(-0.2676)+70
h(0)= -0.3129224346+70
h(0)= 69.98

So the rider be at the bottom of the Ferris wheel at 69.68 seconds?