a = 1st term A.P. ... d = common difference
10 a + 45 d = 85 ... 2 a + 9 d = 17
(3a + 3d) / (4a + 6d) = (4a + 6d) / (8a + 28d)
two equations and two unknowns
The third,fourth and eight term of A.P form first three consecutive term of G.P.if the sum of the first ten term of A.P is 85.calculate the first term of both A.P and G.P,common ratio and sum of 5 term of G.P
3 answers
(4a + 6d) (8 a + 28d)
Helpful for the Answer on qn above