This is algebra II?
Let AB be the number.
A-6=B
A*10+B-36=B(10)+A
the tens digit of a two digit number is 6 more than the units digit. the number is 36 more than the number when the digits are reversed/ what is the number?
8 answers
when i solve for the variables i cancel everything and i don't get an answer
i solved for the longer equation and got a=b+4
i put that in the smaller equation and got b-2=b
iam confused
i put that in the smaller equation and got b-2=b
iam confused
There is no solution to your question
the only possible cases of a two digit number where the tens digit is 6 more than the units digit are:
60, 71, 82, and 93
the numbers with the digits reversed would be
06, 17, 28, and 39
in each case the difference would be 54, never 36
the only possible cases of a two digit number where the tens digit is 6 more than the units digit are:
60, 71, 82, and 93
the numbers with the digits reversed would be
06, 17, 28, and 39
in each case the difference would be 54, never 36
I'm just really confused about everything
5-(45sin+cos2)-y+344=
alebra like
what is it like in high school