Asked by Anonymous
The temperature difference between the inlet and the outlet of an air-cooled engine is 30.0K. The engine generates 7.0kW of waste power that the air extracts from the engine. Calculate the rate of flow of air (in kg s^-1) needed to extract this power?
SPECIFIC HEAT CAPACITY of air (at constant pressure)= 1.01 x10^3J kg^-1 K^-1
SPECIFIC HEAT CAPACITY of air (at constant pressure)= 1.01 x10^3J kg^-1 K^-1
Answers
Answered by
bobpursley
power extracted=airmass/sec*heatcapacity*tempdifference.
solve for air mass rate
= power extracted/(heatcap*tempdiff)
solve for air mass rate
= power extracted/(heatcap*tempdiff)
Answered by
nnnnn
Q=Power * time
m= Q/shc*temp change
m= Q/shc*temp change
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