the temperature difference between the inlet and outlet of an air_cooled engine is 30.0K. The engine generates 7.0kWof waste power that the air extracts from the engine. calculate the rate of flow of of air in kg/s needed to extract this power. shc of air at constant pressure is 1.01×10^3JKg^-1K^-1

Answer 1

air flow= 30K*7kW/(1.01e3J/(KgK))
air flow= 30 kW/(1.10kj)*Kg
but kiloWatts= kiloJoule /sec so
air flow= 30Kg/1.01sec= ... check my work.