The swan below is composed of several triangles. Use the given information and the figure to find each angle measure. Note: Figure not drawn to scale.

Given: ΔABC is equilateral; DE¯¯¯¯¯¯¯¯≅CE¯¯¯¯¯¯¯¯≅EF¯¯¯¯¯¯¯¯
\overline{DE}\cong\overline{CE}\cong\overline{EF}; KO¯¯¯¯¯¯¯¯≅FO¯¯¯¯¯¯¯¯
\overline{KO}\cong\overline{FO}; JN¯¯¯¯¯¯¯¯≅JO¯¯¯¯¯¯¯
\overline{JN}\cong\overline{JO}; ∠BCD ≅ ∠BDC; CGF ≅ ∠CFG; ∠HKN ≅ ∠HNK; ΔGCF ≅ ΔGKF ≅ ΔJHM; ΔKFH ≅ ΔKLH

Triangular Swan Portfolio

Print the document so that you can write on it and mark the pictureshowin congruent sides​

(2 points)
1. m∠ABC =

2. m∠BCA =

3. m∠CAB =

4. m∠BCD =

5. m∠BDC =

6. m∠CBD =

Question 3
(2 points)
7. m∠EDC =

8. m∠ECD =

9. m∠CED =

10. m∠ECF =

11. m∠EFC =

12. m∠CEF =

Question 4
(2 points)
13. m∠CGF =

14. m∠CFG =

15. m∠GCF =

16. m∠KGF =

17. m∠KFG =

18. m∠GKF =

Question 5
(2 points)
19. m∠FKH =

20. m∠FHK =

21. m∠KFH =

22. m∠KHL =

23. m∠HKL =

24. m∠KLH =

Question 6
(2 points)
25. m∠HJM =

26. m∠HMJ =

27. m∠JHM =

28. m∠OFK =

29. m∠OKF =

30. m∠KOF =

Question 7
(2 points)
31. m∠HKN =

32. m∠HNK =

33. m∠OKN =

34. m∠JNO =

35. m∠JON =

36. m∠NJO

1 answer

To find the measures of the angles in the triangular swan based on the information provided, we can apply the properties of congruent triangles, angles, and the nature of equilateral triangles. Let's go through the questions step by step, applying the given information about congruencies and angle relationships.

Equilateral Triangle Properties

  • An equilateral triangle has three equal angles; each angle measures \(60^\circ\).
  • Therefore, in triangle \(ABC\):
    1. \(m\angle ABC = 60^\circ\)
    2. \(m\angle BCA = 60^\circ\)
    3. \(m\angle CAB = 60^\circ\)

Given Information and Applications

Triangles formed by segments:

  1. For angles BCD and BDC being congruent (\(m\angle BCD = m\angle BDC\)):

    • Let \(m\angle BCD = m\angle BDC = x\).
    • Hence, \(m\angle CBD = 180^\circ - 2x\) because the angles in a triangle sum to \(180^\circ\).
  2. For triangle CDE (with \(DE \cong CE \cong EF\)), all angles will be equal (since all sides are equal):

    • Let \(m\angle CED = m\angle EDC = m\angle ECD = y\).
    • Thus, \(3y = 180^\circ\) → \(y = 60^\circ\).
  3. Triangle Congruence:

    • If \(ΔGCF ≅ ΔGKF\), then corresponding angles will be equal.
    • \(m\angle CGF = m\angle KGF\) etc.

Key Angle Calculations

Now let's compile the information together.

Answers:

  1. \(m\angle ABC = 60^\circ\)

  2. \(m\angle BCA = 60^\circ\)

  3. \(m\angle CAB = 60^\circ\)

  4. Let’s assume \(m\angle BCD = x\), \(m\angle BDC = x\):

    • \(2x + (180º - 2x) = 180º\), thus \(m\angle CBD = 180^\circ - 2x\).
    • This results in \(x\) = remaining angles as derived from others.

For angles 4, 5, and 6:

  • To derive the measure of angles \(BCD\), \(BDC\), and \(CBD\), if \(m\angle BCD = m\angle BDC\): \[ x + x + (180 - 2x) = 180 \rightarrow 2x + 180 - 2x = 180 \]

This implies \(m\angle CBD = y\) as stated above –evaluating these equations shows details about isosceles triangles.

Continuing similarly, applying triangle congruences and relationships, we get:

  1. \(m\angle EDC = 60^\circ\)

  2. \(m\angle ECD = 60^\circ\)

  3. \(m\angle CED = 60^\circ\)

  4. \(m\angle ECF = 60^\circ\)

  5. \(m\angle EFC = 60^\circ\)

  6. \(m\angle CEF = 60^\circ\)

  7. \(m\angle CGF = z\) (as defined earlier via congruency)

  8. \(m\angle CFG = z\)

  9. \(m\angle GCF = z\)

  10. \(m\angle KGF = w\)

  11. \(m\angle KFG = w\)

  12. \(m\angle GKF = w\)

  13. \(m\angle FKH = \alpha\)

  14. \(m\angle FHK = \alpha\)

  15. \(m\angle KFH = \alpha\)

  16. \(m\angle KHL = \beta\)

  17. \(m\angle HKL = \beta\)

  18. \(m\angle KLH = \beta\)

  19. \(m\angle HJM = \theta\)

  20. \(m\angle HMJ = \theta\)

  21. \(m\angle JHM = \theta\)

  22. \(m\angle OFK = \gamma\)

  23. \(m\angle OKF = \gamma\)

  24. \(m\angle KOF = \gamma\)

  25. \(m\angle HKN = \delta\)

  26. \(m\angle HNK = \delta\)

  27. \(m\angle OKN = \delta\)

  28. \(m\angle JNO = \epsilon\)

  29. \(m\angle JON = \epsilon\)

  30. \(m\angle NJO = \epsilon\)

Final Note:

  • The specific numerical angles may need additional specifics from the figure or context provided to produce final angle measures based on triangle relationships or isosceles configurations. Each of the \(x, y, z, w, \alpha, \beta, \theta, \gamma, \delta, \epsilon\) would need measurement from either provided angles or constraints to pin exact values.