The swan below is composed of several triangles. Use the given information and the figure to find each angle measure. Note: Figure not drawn to scale.

Question

Given: ΔABC is equilateral; DE¯¯¯¯¯¯¯¯≅CE¯¯¯¯¯¯¯¯≅EF¯¯¯¯¯¯¯¯
\overline{DE}\cong\overline{CE}\cong\overline{EF}; KO¯¯¯¯¯¯¯¯≅FO¯¯¯¯¯¯¯¯
\overline{KO}\cong\overline{FO}; JN¯¯¯¯¯¯¯¯≅JO¯¯¯¯¯¯¯
\overline{JN}\cong\overline{JO}; ∠BCD ≅ ∠BDC; CGF ≅ ∠CFG; ∠HKN ≅ ∠HNK; ΔGCF ≅ ΔGKF ≅ ΔJHM; ΔKFH ≅ ΔKLH

Triangular Swan Portfolio

Print the document so that you can write on it and mark the pictureshowin congruent sides​

(2 points)
1. m∠ABC =

2. m∠BCA =

3. m∠CAB =

4. m∠BCD =

5. m∠BDC =

6. m∠CBD =

Question 3
(2 points)
7. m∠EDC =

8. m∠ECD =

9. m∠CED =

10. m∠ECF =

11. m∠EFC =

12. m∠CEF =

Answer 1

To solve the problem, let's analyze the given information step by step.

Step 1: Analyze Triangle ABC

Since \( \Delta ABC \) is equilateral:

• All angles are equal. The measure of each angle in an equilateral triangle is given by: \[ m\angle ABC = m\angle BCA = m\angle CAB = \frac{180^\circ}{3} = 60^\circ \]

So:

1. \( m\angle ABC = 60^\circ \)
2. \( m\angle BCA = 60^\circ \)
3. \( m\angle CAB = 60^\circ \)

Step 2: Analyze Angles BCD and BDC

Given that \( \angle BCD \cong \angle BDC \), we can denote: \[ \angle BCD = \angle BDC = x \] From the triangle sum theorem: \[ m\angle ABC + m\angle BCD + m\angle BDC = 180^\circ \] Substituting the known values: \[ 60^\circ + x + x = 180^\circ \] \[ 60^\circ + 2x = 180^\circ \] \[ 2x = 120^\circ \] \[ x = 60^\circ \] Thus: 4. \( m\angle BCD = 60^\circ \) 5. \( m\angle BDC = 60^\circ \) 6. Since \( m\angle CBD = 180^\circ - m\angle ABC - m\angle BDC \): \[ m\angle CBD = 180^\circ - 60^\circ - 60^\circ = 60^\circ \]

Step 3: Analyze Triangle CDE and Triangle ECF

Regarding triangle \( CDE \): Given that \( DE \cong CE \cong EF \), triangle \( CDE \) is also equilateral. Therefore: 7. \( m\angle EDC = 60^\circ \) 8. \( m\angle ECD = 60^\circ \) 9. \( m\angle CED = 60^\circ \)

For triangle \( ECF \) (since \( ECF \) is not specified as equilateral, but given the congruency relationships and symmetry): 10. \( m\angle ECF = 60^\circ \) 11. \( m\angle EFC = 60^\circ \) 12. Similarly, \( m\angle CEF = 60^\circ \)

Summary of Angles

1. \( m\angle ABC = 60^\circ \)
2. \( m\angle BCA = 60^\circ \)
3. \( m\angle CAB = 60^\circ \)
4. \( m\angle BCD = 60^\circ \)
5. \( m\angle BDC = 60^\circ \)
6. \( m\angle CBD = 60^\circ \)
7. \( m\angle EDC = 60^\circ \)
8. \( m\angle ECD = 60^\circ \)
9. \( m\angle CED = 60^\circ \)
10. \( m\angle ECF = 60^\circ \)
11. \( m\angle EFC = 60^\circ \)
12. \( m\angle CEF = 60^\circ \)

All of the angles found in triangles \( ABC \), \( CDE \), and \( ECF \) are \( 60^\circ \) due to the properties of equilateral triangles and the given conditions of congruence.