The surface area of the net diagram of a right circular cylinder can be calculated as:
Surface Area = 2πr^2 + 2πrh
Given that the total surface area is 522.81 feet^2 and the value of π is 3.14, we can substitute these values into the equation:
522.81 = 2(3.14)r^2 + 2(3.14)rh
Simplify the equation:
261.405 = 3.14r^2 + 6.28rh
Since we are interested in finding the height of the curved surface, we can isolate the 'h' term in the equation:
h = (261.405 - 3.14r^2) / (6.28r)
Now we need the value of the radius (r) to solve for the height of the curved surface. We are missing that information in the given problem.
The surface area of the net diagram of the right circular cylinder is 522.81 feet2 . Find the height of the curved surface. Use 3.14 for π .
3 answers
its 9
Given that the radius of the right circular cylinder is 9 feet, we can substitute this into the equation:
h = (261.405 - 3.14(9)^2) / (6.28(9))
h = (261.405 - 254.34) / 56.52
h = 7.065 / 56.52
h ≈ 0.125 feet
Therefore, the height of the curved surface of the cylinder is approximately 0.125 feet.
h = (261.405 - 3.14(9)^2) / (6.28(9))
h = (261.405 - 254.34) / 56.52
h = 7.065 / 56.52
h ≈ 0.125 feet
Therefore, the height of the curved surface of the cylinder is approximately 0.125 feet.