The net diagram of the right circular cylinder consists of two circles (top and bottom) and a rectangle (the side).
The formula for the surface area of a cylinder is given by:
Surface Area = 2πr^2 + 2πrh
where r is the radius of the base, h is the height, and π is the constant pi.
Given that the radius of the circles is 3 ft, we have:
Surface Area = 2π(3)^2 + 2π(3)h
Surface Area = 18π + 6πh
Surface Area = 24π + 6πh
Given that the surface area is 395.64 ft^2, we can substitute this into the equation and solve for h:
395.64 = 24π + 6πh
395.64 = 24(3.14) + 6(3.14)h
395.64 = 75.36 + 18.84h
18.84h = 320.28
h = 320.28 / 18.84
h = 16.99
Therefore, the height of the net diagram of the right circular cylinder is approximately 16.99 feet.
If the surface area of the net diagram of the right circular cylinder is 395.64 feet2 , find the height of the net diagram. Use 3.14 for π .
Radius of both circles = 3
1 answer
1 answer