The surface area of a square pyramid can be calculated using the equation S=12lp+B%0D%0A𝑆%0D%0A=%0D%0A1%0D%0A2%0D%0A𝑙%0D%0A𝑝%0D%0A+%0D%0A𝐵%0D%0A . Rearrange the surface area equation for the quantity of interest B%0D%0A𝐵%0D%0A .(1 point)

Answer 1

To rearrange the surface area equation for $B$ (the area of the base of the square pyramid), we start with the equation for the surface area $S$:

$$S=\frac{1}{2}lp+B$$

Here, $l$ is the slant height, $p$ is the perimeter of the base, and $B$ is the area of the base.

To isolate $B$, we can rearrange the equation as follows:

1. Subtract $\frac{1}{2}lp$ from both sides: $$B=S-\frac{1}{2}lp$$

So the rearranged equation for the area of the base $B$ is:

$$B=S-\frac{1}{2}lp$$