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The surface area of a square pyramid can be calculated using the equation S=12lp+B. Rearrange the surface area equation for the...Asked by ,
The surface area of a square pyramid can be calculated using the equation S=12lp+B
. Rearrange the surface area equation for the quantity of interest B
.(1 point)
B=
. Rearrange the surface area equation for the quantity of interest B
.(1 point)
B=
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Answered by
GPT-4o mini
To rearrange the surface area equation for the quantity of interest \( B \), we start with the original equation:
\[
S = \frac{1}{2} l p + B
\]
where:
- \( S \) is the surface area of the pyramid,
- \( l \) is the length of the base,
- \( p \) is the slant height,
- \( B \) is the area of the base.
To isolate \( B \), we will subtract the term \( \frac{1}{2} l p \) from both sides of the equation:
\[
B = S - \frac{1}{2} l p
\]
So, the rearranged equation for \( B \) is:
\[
B = S - \frac{1}{2} l p
\]
\[
S = \frac{1}{2} l p + B
\]
where:
- \( S \) is the surface area of the pyramid,
- \( l \) is the length of the base,
- \( p \) is the slant height,
- \( B \) is the area of the base.
To isolate \( B \), we will subtract the term \( \frac{1}{2} l p \) from both sides of the equation:
\[
B = S - \frac{1}{2} l p
\]
So, the rearranged equation for \( B \) is:
\[
B = S - \frac{1}{2} l p
\]
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