The sum to infinity of a g.p is 60. If the first term of the series is 12. Find it's second term
2 answers
Sum to infinity s=60. First term,a=12. S =a÷1_r=60÷1=12÷1_r. 60(1_r)=12=60_60r=12. 60_12=60r=48÷60=60r÷60. r=48÷60.you reduce into lower term. that is 12 cancel 48 which is equal to 4 and 15 cancel 60 , 5 times. r= 4÷5. Which means that the second term,T2=ar=12×4÷5=48÷5
A lot of verbiage there, your solution is hard to read.
S∞ = a/(1-r)
60 = 12/(1-r)
5 = 1/(1-r)
1 = 5 - 5r
5r = 4
r 4/5
term(2) = ar = 12(4/5) = 48/5
S∞ = a/(1-r)
60 = 12/(1-r)
5 = 1/(1-r)
1 = 5 - 5r
5r = 4
r 4/5
term(2) = ar = 12(4/5) = 48/5
2 answers