Let the three consecutive odd integers be represented as \( x \), \( x + 2 \), and \( x + 4 \). The equation for the sum of these integers is:
\[ x + (x + 2) + (x + 4) = 39 \]
Simplifying the left side, we have:
\[ 3x + 6 = 39 \]
Subtracting 6 from both sides, we get:
\[ 3x = 33 \]
Dividing by 3 gives:
\[ x = 11 \]
Thus, the three consecutive odd integers are:
- \( x = 11 \)
- \( x + 2 = 13 \)
- \( x + 4 = 15 \)
Therefore, the integers, from least to greatest, are:
11, 13, 15.
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