so we want
2 + 4 + 6 + ... = 930
this is an arithmetic series where
a=2 , d=2 , n = ?
n/2[2a + (n-1)d) = 930
n/2[4 + (n-1)(2)] = 930
n^2 + n - 930 = 0
(n+31)(n-30) = 0
n = 30 or n=-31, but n has to be a positive whole number.
there were 30 terms
The sum of the first X consecutive even numbers is 930. Find X.
10
35
30
41
Explain your solution.
1 answer