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the sum of the first four terms is 26 and that of the next four terms is 74. find the values of (a) the first terms (b) the common difference.

2 answers

Assuming we have an AS
sum(4) = 26 ---> 2(2a + 3d) = 26
2a + 3d = 13

sum(8) = 26+74 =100 --> 4(2a + 7d) = 100
2a + 7d = 50

subtract : 4d = 37
d = 37/4
in 2a + 3d = 13
2a + 111/4 = 13
a = -59/8
Wonderful. Thanks
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