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The sum of the digits in a three digit number is nine.The tens digit is half the sum of the other two and the hundreds digit is half the unit digit.Find the total value of the second digit

5 answers

h + t + u = 9

2 t = h + u

solve for t

and u = 2h

What is the answer?

a+b+c=9
2b=a+c

t=h+u/2

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