The sum of the ages of a woman and her daughter is 46years.In 4 years, the ratio of their ages will be 7:2. Find their present ages.

Answer 1

In four years, the total of the ages will be 46+4+4=54 years.
The ratio in four years will be 7:2
So
age of daughter in four years
= 54*(2/(7+2))=12
age of mother in four years
= 54*(7/(7+2))=42

Continue to find their present ages.

Answer 2

Let the woman's age=x
Let the daughter's age=y
Therefore
(x+y)=46
Make x the subject of theach above equation.
; x=46-y (equation 1)
4 years ago;
The woman=x+4
the daughter =y+4

The ratio is
7:2=(x+4):(y+4)
Cross multiply
7(y+4)=2 (x+4)
7y+28=2x+8 (equation 2)

Substitute (equation 1) into ( equation 2)

7y+28=2(46-y)+8
7y+28=92 -2y+8
Group like terms
7y+2y=92+8-28
9y=72
Divide all sides by 9

Y=8.

Substitute y=8 into (equation 1)
°: x=46-y
x=46-8
X=38.

Therefore
Woman's age =38
Daugher's age=8

Answer 3

Very comprehensive, but easy to understand

Answer 4

your mum

Answer 5

Great, well explanation

Answer 6

Thank you! I'm glad you found it helpful. If you have any other questions, feel free to ask.