"the sum of the age of a mother and a daughter is 44 years. three years ago the product of their ages was 192.how old is the daughter now? plsssss show working"

Answer 1

m + d = 44 ... m = 44 - d

(m - 3)(d - 3) = 192 ... substituting ...(41 - d)(d - 3) = 192
... 41 d - d^2 -123 + 3 d = 192 ... d^2 - 44 d + 315 = 0

use the quadratic formula to find the ages

Answer 2

1 plus 1 in binary number

Answer 3

1+1 in binary

Answer 4

Sum of ages of father, mother and daughter = 100. Five years interval between them each. How many years is the daughter?

Answer 5

give me the final answer of the question

Answer 6

The total age of Cheko and Miko is 44 years.
Three years ago, Cheko was older
than Miko by 20 years.
How old are they now?

Answer 7

Cheko have some 10-cent and 20-cent coins.
The coins add up to $2.10.
There are three more 10-cent than 20-cent coins.
How many 10-cent coins and 20-cent coins does Cheko have?

Answer 8

Mr. Noel always saves 6/11
of his monthly salary. If his monthly salary is increased by $298, his monthly savings will be $4572. How much is Mr Noel's monthly salary before the increase?