3/2 (2a+2d) = 39
(a+d+5)/(a+1) = (a+2d+12)/(a+d+5)
a=11, d=2
AP: 11,13,15
GP: 12,18,27
a=26, d= -13
AP: 26, 13, 0
GP: 27,18,12
The sum of the 3 terms in arithmetic sequence is 39.if these numbers is increased by 1,5 and 12 respectively the numbers would be in geometric progression. find the second term of the geometric progression?
1 answer