Let's assume that the first consecutive integer is x. Then, the next four consecutive integers can be expressed as (x+1), (x+2), (x+3), and (x+4)
According to the problem statement, the sum of these five integers is 75. So we can write an equation as follows:
x + (x+1) + (x+2) + (x+3) + (x+4) = 75
Simplifying this equation, we get:
5x + 10 = 75
Subtracting 10 from both sides, we get:
5x = 65
Dividing by 5, we get:
x = 13
So the first consecutive integer is 13, and the third consecutive integer can be found by adding 2 to 13:
x + 2 = 13 + 2 = 15
Therefore, the third integer in the sequence is 15.
The sum of five consecutive integers is 75.
What is the third number?
2 answers
or, suppose they were all equal. Then he numbers would be
15, 15, 15, 15, 15
Now just adjust the ends by 2, and the next two inner numbers by 1.
13, 14, 15, 16, 17
The middle one stays 15.
15, 15, 15, 15, 15
Now just adjust the ends by 2, and the next two inner numbers by 1.
13, 14, 15, 16, 17
The middle one stays 15.