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The sum of first 8th terms of an A.P is 160 while the sum of 20 term is 880.Find a. The 43rd term b.The sum of 12 term

2 answers

8/2 (2a+7d) = 160
20/2 (2a+19d = 880)
solve for a and d, and then you want
a+42d
S12 = 12/2 (2a+11d)
The 9th term of an A.P is 52 while the 12th term is 20find the of its first 20 term
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