Get the acceleration from F = ma
During the first period,
a = F{0}/m and the displacement is
(1/2)*(F{0}/m)*t{0}^2
During the second period it travels twice as far, since the period of acceleration at the higher (doubled) rate is the same.
Add the two displacements
{ The subscripts are in curly brackets }
A mass m is at rest on a horizontal frictionless surface at t=0. Then a constant force F{0} acts on it for a time t{0}. Suddenly, the force doubles to 2F{0} and remains constant until t=2t{0}. Determine the total distance D traveled from t=0 to t=2t{0}. Express your answer in terms of F{0}, t{0}, and m.
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