The standard deviation of a probability distribution table is 26.6 and the mean is 674.0. During an event, you receive the result of 622.3. Determine whether this value is considered usual or unusual and tell why.(1 point)ResponsesUsual, because the result is within the range of the minimum and maximum usual values.Usual, because the result is within the range of the minimum and maximum usual values.Usual, because the result is less than the minimum usual value.Usual, because the result is less than the minimum usual value.Unusual, because the result is within the range of the minimum and maximum usual values.Unusual, because the result is within the range of the minimum and maximum usual values.Unusual, because the result is less than the minimum usual value.

1 answer

To determine whether the result of 622.3 is considered usual or unusual in relation to the mean (674.0) and standard deviation (26.6), we typically use the concept of "usual" values being within 2 standard deviations from the mean.

First, calculate the range of usual values:

  1. Calculate the lower bound: \[ \text{Lower Bound} = \text{Mean} - 2 \times \text{Standard Deviation} = 674.0 - 2 \times 26.6 = 674.0 - 53.2 = 620.8 \]

  2. Calculate the upper bound: \[ \text{Upper Bound} = \text{Mean} + 2 \times \text{Standard Deviation} = 674.0 + 2 \times 26.6 = 674.0 + 53.2 = 727.2 \]

Now, the usual range is between 620.8 and 727.2. The result of 622.3 falls within this range:

  • 622.3 is greater than 620.8 (lower bound).
  • 622.3 is less than 727.2 (upper bound).

Since 622.3 is within the calculated range of usual values, we determine that the value is Usual.

The correct response is: Usual, because the result is within the range of the minimum and maximum usual values.