a. mean = np = 200(.6) =120
Standard deviation = sqrt((.6*.4*200))= sqrt(48)
Assume a binomial probability distribution has p = .60 and n = 200.
a)What are the mean and standard deviation (to 2 decimals)?
b)Why can the normal probability distribution be used to approximate this binomial distribution?
c)What is the probability of 100 to 110 successes (to 4 decimals)?
d)What is the probability of 130 or more successes (to 4 decimals)?
e)What is the advantage of using the normal probability distribution to approximate the binomial probabilities?
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