Assume that a procedure yields a binomial distribution with a trial repeated

times. Use either the binomial probability formula (or a technology like Excel or StatDisk) to find the probability of
successes given the probability
of failure on a single trial.

(Report answer accurate to 4 decimal places.)


0.1787
Incorrect0.1493

1 answer

To calculate the probability of successes in a binomial distribution, you can use the binomial probability formula:

\[ P(X = k) = \binom{n}{k} p^k (1 - p)^{n - k} \]

where:

  • \( n \) is the number of trials,
  • \( k \) is the number of successes,
  • \( p \) is the probability of success on a single trial,
  • \( \binom{n}{k} \) is the binomial coefficient, calculated as \( \frac{n!}{k!(n-k)!} \).

If you provide the values for \( n \) (the number of trials), \( k \) (the number of successes), and \( p \) (the probability of success), I can help you calculate the probability.

For example, if there are \( n = 10 \) trials, \( k = 3 \) successes, and \( p = 0.5 \) (probability of success), the calculation would look like this:

  1. Compute the binomial coefficient \( \binom{10}{3} \): \[ \binom{10}{3} = \frac{10!}{3!(10-3)!} = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} = 120 \]

  2. Calculate \( (0.5)^3 \) and \( (1 - 0.5)^{7} \): \[ (0.5)^3 = 0.125 \] \[ (0.5)^{7} = 0.0078125 \]

  3. Put it all together: \[ P(X = 3) = 120 \times 0.125 \times 0.0078125 \approx 0.1172 \]

You can use similar calculations or software like Excel or StatDisk to find the exact probability.

If you can provide the specific values (n, k, and p), I can assist you with the exact calculation!