Assume that a procedure yields a binomial distribution with a trial repeated n times. Use a binomial probabilities table to find the probability of x successes given the probability p of the success on a given trial N=9 X=0 p=0.30

Answer 1

the equation you need is
P(X=r)=C(n,r)*p^r*(1-p)^(n-r)
C(n,r)=n!/((n-r)!r!)
and n!=n(n-1)(n-2)....(2)1=factorial n

You have everything you need to calculate the required probability.
It turns out that C(n,0)=1 for any positive value of n.

The answer is less than 5%. You can post your answer for a check if you wish.