Let V1 be the speed of the slower train.
let V2 be the speed of the faster train.
Here is what you know:
V2 = V1 + 6
V2 = (230/200)*V1 = (23/20)*V1 = 1.15 V1
Solve by substitution
1.15 V1 = V1 + 6
0.15 V1 = 6
V1 = 40 mph
Use either of the original equations to solve for V2.
The speed of train A is 6 mph slower than the speed of train B. Train A travels 200 miles in the same time it takes train B to travel 230 miles. Find the speed of each train?
1 answer
1 answer