The speed of the car at the base of a 30 ft hill is 45 mi/h. Assuming the driver keeps her foot off the brake and accelerator pedals, what will be the speed of the car at the top of the hill?

Answer 1

Kinetic energy + Potential Energy

(1/2) *m*vf^2 + (1/2)*m*vi^2 = mgh

m=mass
but we we really don't need the mass to figure this problem out since we can factor it out of the equation

Now isolate the vf

vf = sqrt(2*g*h - vi^2)

g=9.81
h=30
vi=45

vf=sqrt(2*9.81*30 - 45^2)
vf=37.899

Can someone check this????? really not sure just gave it a go