Asked by Kayla
The speed of sound in a classroom is 343m/s.
A) A tuning fork of frequency 512Hz is struck. What length of open air tube is required to create a resonant sound at the 1st harmonic?
wavelength=v/f=343/512=0.67m
L=.5wavelength=.5(.67)= 0.335m
B) Fore the same tube, what tuning fork frequency is needed to generate a resonant tone at the 3rd harmonic?
L=1.5wavelength
Therefore: .335=1.5wavelength
wavelength= .223m
f=v/wavelength=343/.223= 1538.12Hz
C)In the same classroom, what is the lowest resonant frequency for a closed air tube of length 45cm?
wavelength=L/.25=.45/.25=1.8
f=V(wavelength)=343(1.8)=617.4Hz
I'm having a really hard time with waves... So I just want to make sure I'm on the right track. Thanks a bunch :)
A) A tuning fork of frequency 512Hz is struck. What length of open air tube is required to create a resonant sound at the 1st harmonic?
wavelength=v/f=343/512=0.67m
L=.5wavelength=.5(.67)= 0.335m
B) Fore the same tube, what tuning fork frequency is needed to generate a resonant tone at the 3rd harmonic?
L=1.5wavelength
Therefore: .335=1.5wavelength
wavelength= .223m
f=v/wavelength=343/.223= 1538.12Hz
C)In the same classroom, what is the lowest resonant frequency for a closed air tube of length 45cm?
wavelength=L/.25=.45/.25=1.8
f=V(wavelength)=343(1.8)=617.4Hz
I'm having a really hard time with waves... So I just want to make sure I'm on the right track. Thanks a bunch :)
Answers
Answered by
Damon
http://hyperphysics.phy-astr.gsu.edu/hbase/Waves/opecol.html
Answered by
Damon
so A yes .335
B yes 1536
C
well lambda = 1.8 meters all right
but
1.8 = v T = v/f
f = v/1.8 = 343/1.8 = 1.91 Hz
keep that distance = speed *time in mind
B yes 1536
C
well lambda = 1.8 meters all right
but
1.8 = v T = v/f
f = v/1.8 = 343/1.8 = 1.91 Hz
keep that distance = speed *time in mind
Answered by
Damon
191 Hz
Answered by
Kayla
Oh I mixed up my formula!! Thank you for catching that :) I hate stupid mistakes that I should know better than.
Answered by
Damon
When in danger or in doubt, keep the units and make sure they come out right.
meters = meters/second * seconds :)
L = v T
f = 1/seconds
so
f = v/L = (meters/ second) / meters
= 1/seconds
meters = meters/second * seconds :)
L = v T
f = 1/seconds
so
f = v/L = (meters/ second) / meters
= 1/seconds
Answered by
Kayla
Ok, that's a good idea, I struggle with the units sometimes so I should try & keep track anyways. Thanks again :)
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