Vo = 20mi/h * 5280Ft/mi * 1h/3600s. = 29.3 m/s.
V = 30/20 * 29.3 = 44 m/s.
a = (V-Vo)/t = (30-20)/t = 10/t.
d = 0.5*a*t^2 = 500 Ft.
0.5*(10/t)*t^2 = 500.
5t = 500.
t = 100 s.
a = 10/t = 10/100 = 0.10 Ft/s^2
The speed of a train increased from 20 mi/hr to 30 mi/hr in a distance of 500 ft. Calculate the average acceleration in ft/s2
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