time for faster train --- t hours
time for slower train === t + 1.5
distance of faster train = 60t
distance of slower train = 40(t+1.5)
but the distances are the same .....
can you take it from there.
time for slower train === t + 1.5
distance of faster train = 60t
distance of slower train = 40(t+1.5)
but the distances are the same .....
can you take it from there.
Let's assume the time taken by the freight train to make the trip is 't' hours. Therefore, the time taken by the passenger train to make the same trip will be 't - 1.5' hours, as mentioned in the problem.
We know that distance = speed × time.
For the freight train:
Distance = Speed × Time
Distance = 40 mi/h × t hours
Distance = 40t miles
For the passenger train:
Distance = Speed × Time
Distance = 60 mi/h × (t - 1.5) hours
Distance = 60(t - 1.5) miles
Since both trains travel the same distance, we can set up the equation:
40t = 60(t - 1.5)
Now, let's solve this equation to find the value of 't', which represents the time taken by the freight train to make the trip.