Let's assume the speed of the current is x mph.
When the boat is traveling with the current, the effective speed of the boat is 20 + x mph. Given that it takes 4 hours to cover a distance of 100 miles, we can set up the equation as follows:
100 = (20 + x) * 4
Dividing both sides by 4, we have:
25 = 20 + x
Subtracting 20 from both sides, we get:
x = 5 mph
When the boat is traveling against the current, the effective speed of the boat is 20 - x mph. Given that it takes 6 hours and 40 minutes (or 6.67 hours) to cover the same distance of 100 miles, we can set up another equation:
100 = (20 - x) * 6.67
Dividing both sides by 6.67, we have:
x = 20 - (100/6.67)
Simplifying, we get:
x ≈ 20 - 15 ≈ 5 mph
Therefore, the speed of the current is 5 mph.
The speed of a boat in still water is 20 mph. It travels from one pier to another with the current in 4 hours and back against the current in 6 hours and 40 minutes. If the distance between the piers is 100 miles, what is the speed of the current?
1 answer