high tide:
x^2 + 7^2 = 25^2
x^2 = 576
x = 24
low tide:
x^2 + 15^2 = 25^
x^2 = 400
x = 20
The distance change is 4 ft
A boat is tied to a pier with a 25-foot rope so that the distance between the top of the pier and the top of the boat deck is 7 feet. If the water level s down 8 feet with the low tide , how much closer ( in feet) is the boat to the base of the pier? Assume the rope is always taut? Shows your work
1 answer
1 answer