The specific heat of ice is 0.5 calories/gram.

60 grams of ice will require _____ calories to raise the temperature 1°C.

so i just do 0.5/60 ??

5 answers

You use those numbers but not that way.
mass ice x specific heat ice x (Tfinal-Tinitial).
60 g x 0.5 cal/g x (1) = ??
and I got 30.
correct?
i got 30
right.
thank you