The specific heat of granite is 0.80 kJ/kg·°C. If 2.0 MJ of heat are added to a 100−kg granite statue of James Prescott Joule that is originally at 18°C, what is the final temperature of the statue?

Answer 1

800 Joules / kg deg C

What is MJ ? I am familiar with mJ which is .001 Joules
Do you mean Megajoule maybe 2.0 * 10^6 Joules?
if so then
2.0 *10^6 = 800 * 100 * (T-18)
2.0*10^6 = 8 *10^4 (T-18)
25 = T-18
T = (25 + 18) deg C

Answer 2

q = mass x specific heat x (Tfinal-Tinitial)
q = 2E6 joules
mass = 100 kg
specific heat = 800 J/kg*C
Tfinal = ?
Tinitial = 18 C
Post your work if you need additional assistance.

Substitute and solve for Tfinal