➢ The solution is: *Hypertonic* <OR> *Hypotonic* <OR> *Isotonic*

➢ Water will flow: *into the cell* <OR> *out of the cell* <OR> *in and out of the cell at the same rate*
➢ The cell will: *expand and possibly burst* <OR> *shrink and get smaller* <OR> *stay the same*
➢ The solution is_____________________
➢ Water will flow _____________________ 40% NaCI
➢ The cell will ______________________ 60% H20

1 answer

To analyze the given conditions of a solution with 40% NaCl and 60% water, we need to determine whether this solution is hypertonic, hypotonic, or isotonic compared to the inside of a typical cell (which has an approximate saline concentration of around 0.9% NaCl).

  1. The solution is: Hypertonic (40% NaCl is a very high concentration of solute compared to the saline concentration in the cell).

  2. Water will flow: out of the cell (water moves from an area of lower solute concentration (inside the cell) to an area of higher solute concentration (the hypertonic solution)).

  3. The cell will: shrink and get smaller (as water leaves the cell, it loses volume and shrinks).

So, summarizing:

  • The solution is hypertonic.
  • Water will flow out of the cell.
  • The cell will shrink and get smaller.
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