➢ The solution is: *Hypertonic* <OR> *Hypotonic* <OR> *Isotonic*

➢ Water will flow: *into the cell* <OR> *out of the cell* <OR> *in and out of the cell at the same rate*
➢ The cell will: *expand and possibly burst* <OR> *shrink and get smaller* <OR> *stay the same*
➢ The solution is_____________________
➢ Water will flow _____________________ 40% NaCI
➢ The cell will ______________________ 70% H20

1 answer

To analyze the scenario with a 40% NaCl solution and a 70% H2O solution, let's break down the components:

  1. 40% NaCl solution: This is a hypertonic solution compared to the 70% H2O (which is essentially pure water). The concentration of solute (salt) is higher in the 40% NaCl solution compared to the diluted cell environment.

  2. Water Flow: Since the 40% NaCl solution is hypertonic compared to the inside of the cell (which is assumed to be more dilute), water will flow out of the cell into the solution.

  3. Cell Behavior: As water leaves the cell, it will shrink and get smaller due to loss of water.

Putting that all together:

  • The solution is: Hypertonic
  • Water will flow: out of the cell
  • The cell will: shrink and get smaller

So, the complete statements would be:

  • The solution is Hypertonic.
  • Water will flow out of the cell.
  • The cell will shrink and get smaller.
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