The solubility of copper(ii) tetraoxosulphate vi at 85°c is 60g in 100g and at 15°c is 18.8g in 100g. if 120g of solution saturated at 85°c are cooled to 150°c, what mass of copper(ii) sulphate crystal would be deposted?
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Answer
Your question makes no sense. If you start with T = 85 and you COOL it to 150, that isn't cooling it very much. I assume you meant it was cooled to 15 C. When you correct and repost make sure you call the compound by a correct name. One correct name, approved by the International Union of Pure and Applied Chemicaty (IUPAC) is copper (II) sulfate. The name you used is not accepted by IUPAC.
Ok
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Assuming you meant it was cooled to 15 C, then
60 g in 100 @ 85 and 18.8 g om 100 @ 15 C.
So how much CuSO4 is in the saturated solution @ 85 C. That's
60 x 120/100 = 72 grams. How much will be dissolved @ 15 C. That's
18.8 x 120/100 = 22.6 g
Start with 72 g - 22.6 g dissolved = ? grams CuSO4 deposited.
60 g in 100 @ 85 and 18.8 g om 100 @ 15 C.
So how much CuSO4 is in the saturated solution @ 85 C. That's
60 x 120/100 = 72 grams. How much will be dissolved @ 15 C. That's
18.8 x 120/100 = 22.6 g
Start with 72 g - 22.6 g dissolved = ? grams CuSO4 deposited.
where did you learn to call it copper(ii) tetraoxosulfate (vi)?
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