Asked by Joy

The solubility of copper(ii) tetraoxosulphate vi at 85°c is 60g in 100g and at 15°c is 18.8g in 100g. if 120g of solution saturated at 85°c are cooled to 150°c, what mass of copper(ii) sulphate crystal would be deposted?
Answered by Joy
Answer
Answered by DrBob222
Your question makes no sense. If you start with T = 85 and you COOL it to 150, that isn't cooling it very much. I assume you meant it was cooled to 15 C. When you correct and repost make sure you call the compound by a correct name. One correct name, approved by the International Union of Pure and Applied Chemicaty (IUPAC) is copper (II) sulfate. The name you used is not accepted by IUPAC.
Answered by Joy
Ok
Answered by Joy
Tell me question that we come out in 3rd term exam for ss2
Answered by DrBob222
Assuming you meant it was cooled to 15 C, then
60 g in 100 @ 85 and 18.8 g om 100 @ 15 C.
So how much CuSO4 is in the saturated solution @ 85 C. That's
60 x 120/100 = 72 grams. How much will be dissolved @ 15 C. That's
18.8 x 120/100 = 22.6 g
Start with 72 g - 22.6 g dissolved = ? grams CuSO4 deposited.
Answered by DrBob222
where did you learn to call it copper(ii) tetraoxosulfate (vi)?
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