The slope of the tangent line to the graph y= x^3/x -x at the point (1, -2/3)

I keep getting undefined as a answer but.. I feel like I might be doing something wrong because I feel like that is not the answer, can you help me please?

5 answers

could be the way you typed your equation.

The way you typed it, why not just simplify x^3/x to x^2 ?
That is why I am suspicious about the way it was typed.
Did you mean y = x^(3/x) - x ?
The equation is y= x cubed over x minus x
so;

y= x^3 / x -x

Sorry for being confusingg
y = x^3/x- x would reduce to
y = x^2 - x
and (1,-2/3) would NOT lie on this curve.

So there is something wrong with the way you typed it

Use brackets to establish the correct form
Otherwise this question is bogus.
Okay I sure will! Thanks
Hmmm you know what, I think this problem is an error. Maybe that's why I could not figure it outt?